Streams and Filesystems | The Modern C++ Challenge

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32. Pascal's triangle

Pascal's triangle is a construction representing binomial coefficients. The triangle starts with a row that has a single value of 1. Elements of each row are constructed by summing the numbers above, to the left and right, and treating blank entries as 0. Here is an example of the triangle with five rows:

        1
      1   1
    1   2   1
  1   3   3   1
1   4   6   4   1

To print the triangle, we must:

Shift the output position to the right with an appropriate number of spaces, so that the top is projected on the middle of the triangle's base.
Compute each value by summing the above left and right values. A simpler formula is that for a row i and column j, each new value x is equal to the previous value of x multiplied by (i - j) / (j + 1), where x starts at 1.

The following is a possible implementation of a function that prints the triangle:

unsigned int number_of_digits(unsigned int const i)
{
   return i > 0 ? (int)log10((double)i) + 1 : 1;
}

void print_pascal_triangle...

The Modern C++ Challenge

The Modern C++ Challenge

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32. Pascal's triangle

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The Modern C++ Challenge

The Modern C++ Challenge

Overview of this book

Solutions

32. Pascal's triangle

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